Question

plz answer this question

Answer 1

Answer:

(a). f(x) = x^3-x^2-3x+3

x-1=0

x=1 , now if f(1) =0 the x-1 is a factor of f(x)

f(1)= 1^3 - 1^2- 3×1 +3

= 1-1-3+3

=0

therefore x-1 is a factor of f(x)

Answer 2

Answer:

$(a) = f(x) = {x}^{3} - {x}^{2} - 3x - 3 \\ (x - 1 = 0) \\ (x = 1)$

Now if f(1)=0 the x-1 is a factor of f(x)

$f(1) = {1}^{3} - {1}^{2} - 3 \times 1 + 3$

$= 1 - 1 - 3 + 3$

$= 0$

Therefore (x-1) is a factor of f(x).

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