Question

plz answer this question​

Answer 1

Step-by-step explanation:

f(0)=b

b=0

f(1)=2-3+a+b

a=1

Answer 2

$f(x) = 2 {x}^{3} - 3 {x}^{2} + ax + b \\ if \: x = 0 \\ f(0) = 2 {(0)}^{3} - 3 {(0)}^{2} + a \times 0+ b \\ f(0) = + b \\ if \: x = 1 \\ f(1) = 2 {(1)}^{3} - 3 {(1)}^{2} + a(1) + b \\ f(1) = 2 - 3 + a+ b \\ f(1) = - 1 + a + b \\ \mathfrak \red{ \underline { \underline{hope \: my \: answer \: will \: help \: you}}}$