Question

plz answer this question​

Answer 1

Answer:

37

Step-by-step explanation:

Given:- $\alpha$ and $\beta$ are zeroes..

Solution:-

$= y^2+7y+3\\\\\alpha +\beta = -b/a\\\\\alpha +\beta = \frac{-7}{1} = -7\\\\\\\alpha *\beta =\frac{c}{a} \\\alpha *\beta =\frac{3}{1} =3\\\\\\(\alpha-\beta)^2=(\alpha +\beta)^2-4\alpha \beta \\\\=(-7)^2-4(3)\\\\=49-12\\\\=37$

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