Question

plz answer this question​

Answer 1

we have a,b,c are non zeros and a+b+c=0

a^3+b^3+c^3=3abc

now,

a^2/bc+b^2/ca+c^2/ab= a^3+b^3+c^3/abc=3abc/abc=3

hope it helps you..

^}- this sign is indicated the square....

Answer 2

Answer:

To prove:

If a + b + c = 0, then prove that: a²/bc + b²/ac + c²/ab=3

L. H. S: a²/bc + b²/ac + c²/ab

= a³/abc + b³/abc + c³/abc

=( a³+b³+c³) / (abc)

= (3abc) / (abc)  ( As a³ + b³ + c³ = 3abc )

We get:

=> 3

Therefore,

If a+b+c=0 then a²/bc + b²/ac + c²/ab = 3