Math, asked by jaswinderkaurchahal1, 9 months ago

Plz answer this question

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Answered by AbhijeetSingh20
1

Answer:

THE ANSWER IS:

•TOTAL COST NEEDED TO COVER THE FLOOR IS ₹1,04,625.

Step-by-step explanation:

WE SOLVE LIKE THIS:

•LENGTH OF FLOOR - 4.5 M = 450 CM

•BREADTH OF FLOOR - 3.6 M = 360 CM

•SIDE OF A SQUARE TILE - 6 CM

•COST OF 1 SQUARE TILE - ₹23.25

SO,TOTAL COST TO COVER THE FLOOR:

AREA OF FLOOR = LENGTH x BREADTH

= 450 CM x 360 CM = 1,62,000 CM^2

AREA OF 1 SQUARE TILE - 6 CM x 6 CM

= 36 CM^2

SO,NUMBER OF TILES NEEDED -

= AREA OF FLOOR/AREA OF 1 SQUARE TILE

= 1,62,000/36

= 4500 TILES NEEDED.

SO,TOTAL COST,

=NUMBER OF TILES x COST OF 1 TILE

= 4500 x 23.25

= ₹1,04,625.

THEREFORE,TOTAL COST IS ₹1,04,625.

HOPE IT HELPS YOU.

Answered by utsav96
0
Pls mark as brainliest answer
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