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produce a line YD parallel to XB forming a parrellelogram where YD is equal to 2p-2.
now triangles YDC and YAX, are similar, hence YD/AX = YC/AY = 4
2p-2=4(p-3)
p-1=2p-6
solve and get p as 5
now triangles YDC and YAX, are similar, hence YD/AX = YC/AY = 4
2p-2=4(p-3)
p-1=2p-6
solve and get p as 5
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