Question

plz answer this question​

Answer 1

Answer:

(sinθ+cosθ)^3-2(sin²θcosθ+cos²θsinθ)

Step-by-step explanation:

let siηθ=a and cosθ=b

now put in the question

a³+b³/a+b•ab=(a+b)³-2(a²b+b²a)

now put a=sinθ, b=cosθ