Question

plz answer this question ​

Answer 1

Answer:

The answer is 8.

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ac

so If x²+y²+z²+2xy+2yz+2xz = 64

or, (x+y+z)²=64

or, (x+y+z)=8

Answer 2

x

${x}^{2} + {y +}^{2} + {z}^{2} + 2xyz(z + x + y) = 64$

$( {x + y + z})^{2} (x + y + z) = 64$

$( {x + y + z)}^{3 = 64$

x + y + z = 4

hope it helps you !!