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Answer 1

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Distance between the closest wall(to him) and Sunil = 360mTime after which he hears 1st echo = 4sVelocity of sound  in air= 2(Distance/time)                            = 360*2/4                             = 180m/sLet distance between two walls be x metres Distance of another wall from Sunil = (x - 360)mTime after which he hears echo = 4s + 2s = 6sVelocity of sound = 2(Distance)/time                            = 2(x-360)/6Hence,180 = 2(x-360)/6           ∵(Velocity of sound is constant)⇒1080 = 2(x-360)⇒540 = x - 360⇒x = 540 + 360Distance between two walls=900m