Math, asked by mksaluja, 6 months ago

Plz..answer this question.​

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Answered by Snapskg730
2

Answer:

sec = 2

cos = 1/2

b/h = 1/2

h² = b² + p²

2² = 1² + p²

4-1 = p²

3 = p²

p =  \sqrt{3}

 \sin(q)  =  \frac{ \sqrt{3} }{2}

4 cosQ- √3sinQ

4×1/2 - √3×√3/2

2 - 3/2

1/2

tanQ- cot Q

 \frac{ \sin}{ \cos }  -  \frac{ \cos}{ \sin}

√3/2 × 2 - 1/2 × 2/√3

√3 - 1/√3

2/√3

ans = 1/2 × √3/2 = √3/4

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