Question

plz answer this question ​

Answer 1

√2

Step-by-step explanation:

in ΔABC and ΔAMN

segment MN ║ BC

∠AMN=∠ABC (corresponding angle)

∠ANM=∠ACB (corresponding angle)

∠A si common

so ΔABC≅ΔAMN (CPCT)

given that 2*(area of ΔAMN )= area of ΔABC

so

$</p><p>\begin{gathered}\frac{AM}{MB}=\sqrt{\frac{area of ABC}{area \: of \: AMN}}\\\\\frac{AM}{MB}=\sqrt{\frac{2}{1}}\\\\\frac{AM}{MB}=\sqrt{2}\end{gathered}$