plz answer this question
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Answered by
3
Step-by-step explanation:
We know that the first 40 positive integers divisible by 6 are 6,12,18,....
This is an AP with a = 6 and d = 6
S40= 20[2(6) +(40-1)6] =20[12+234] =4920
2) Multiples of 8 are : 8, 16, 24, 32.....which form an A . P. Hence, the sum of first 15 multiples of 8 = 960.
The odd numbers between 0 and 50 are 1,3,5,7,9…49
Therefore, it can be observed that these odd numbers are in an A.P.
a=1,d=2,l=49
l=a+(n−1)d
49=1+(n−1)2
48=2(n−1)
n−1=24
n=25
S
n
=
2
n
(a+l)
S
25
=
2
25
(1+49)
=
2
25×50
=625
Answered by
2
Answer:
ans12=6720
ans13=960
ans14=625
Step-by-step explanation:
please mark it as brainlest if its correct.
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