Question

plz answer this question

Answer 1

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Answer 2

 In ∆ ACE; AE^2 = AC^2 + CE^2 ……… (1)

In ∆ DCB; BD^2 = DC^2 + CB^2 ……… (2)

In ∆ ACB; AB^2 = AC^2 + CB^2 ……… (3)

In ∆ DCE; DE^2 = DC^2 + CE^2 ……… (4)

Adding equations (1) and (2), we get;

AE^2 + BD^2 = AC^2 + CE^2 + DC^2 + CB^2 …….. (5)

Adding equations (3) and (4), we get;

AB^2 + DE^2 = AC^2 + CB^2 + DC^2 + CE^2 ………. (6)

On comparing the RHS of equations (5) and(6), we get;

AE^2 + BD^2 = AB^2 + DE^2 proved