Question

Plz answer this question

Answer 1

Step-by-step explanation:

PQ∣∣BA,RS∣∣CA

BP=RC

To prove:

(i) △BSR≅△PQC

(ii) RS=CQ

Proof: BP=RC

BC−RC=BC−BP

BR=PC

Now, in △BSR and △PQC

∠B=∠P (Corresponding angles)

∠R=∠C (Corresponding angles)

BR=PC (Proved)

△BSR≅△PQC

BS=PQ

RS=CQ