Math, asked by ankityadav972165, 3 months ago

plz answer this question​

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Answered by Anonymous
1

GiveN:-

Two angles of a triangle are in the ratio 2:3 and the third angle is 60°.

To FinD:-

The other two angles.

SolutioN:-

We know that all angles of a triangle sum up to 180°.

So,

  • Let the other two angles be 2x and 3x.
  • Third angle = 60°

According to the question,

\large\implies{\sf{2x+3x+60\degree=180\degree}}

\large\implies{\sf{5x=180-60}}

\large\implies{\sf{5x=120}}

\large\implies{\sf{x=\dfrac{120}{5}}}

\large\implies{\sf{x=\dfrac{\cancel{120}}{\cancel{5}}}}

\large\therefore\boxed{\bf{x=24.}}

The angles are:-

  1. 2x = 2 × 24 = 48°
  2. 3x = 3 × 24 = 72°
  3. 60°

VerificatioN:-

\large\implies{\sf{48\degree+72\degree+60\degree=180\degree}}

\large\implies{\sf{180\degree=180\degree}}

\large\therefore\boxed{\bf{LHS=RHS.}}

The other two angles are 48° and 72°.

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