Question

plz...answer this question

Answer 1

$\frac{ \tan(50) + \sec(50) }{ \cot(40) + \csc(40) } + \cos(40) \csc(50) \\ = \frac{ \cot(90 - 50) + \ \csc (90 - 50) }{ \cot(40) + \csc(40) } + \cos(40) \sec(90 - 50) \\ = 1 + \frac{ \cos(40) }{ \cos(40) } \\ = 1 + 1 = 2$
Brainliest please!!

Answer 2

this is helpful for u