Math, asked by sr8880799, 3 months ago

plz answer this question​

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Answered by Jash1029
1

Answer:

Above is your answer.......

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Answered by Anonymous
8

Answer :-

Value of x = -1.

Solution :-

\implies\sf{ \dfrac{6x + 1}{3}  + 1 =  \dfrac{x - 3}{6} } \\  \\ \\

\implies\sf{ \dfrac{6x + 1}{3}  + \dfrac{1}{1} =  \dfrac{x - 3}{6} } \\  \\ \\

\implies\sf{ \dfrac{(6x + 1) + 3}{3}=  \dfrac{x - 3}{6} } \\  \\ \\

\implies\sf{ \dfrac{6x + 4}{3}=  \dfrac{x - 3}{6} } \\  \\  \\

\implies\sf{ \dfrac{6x}{3} +  \dfrac{4}{3} =  \dfrac{x}{6} -  \dfrac{3}{6}  } \\  \\ \\

\implies\sf{2x+  \dfrac{4}{3} =  \dfrac{x}{6} -  \dfrac{1}{2}  } \\  \\ \\

\implies\sf{2x -  \dfrac{x}{6} = -  \dfrac{1}{2}  -  \dfrac{4}{3}  } \\  \\ \\

\implies\sf{ \dfrac{12x - x}{6} =  \dfrac{ - 3 - 8}{6} } \\  \\ \\

\implies\sf{ \dfrac{11x}{6} = \dfrac{ - 11}{6} } \\  \\ \\

\implies\sf{11x =  - 11x} \\  \\ \\

\implies\boxed{\sf\red{x =  - 1}} \\  \\

Therefore, Value of x = -1.

Verification :-

\implies\sf{ \dfrac{6x + 1}{3}  + 1 =  \dfrac{x - 3}{6} } \\  \\

\implies\sf{ \dfrac{6( - 1)+ 1}{3}  + 1 =  \dfrac{ - 1 - 3}{6} } \\  \\

\implies\sf{ \dfrac{ - 5}{3}  + 1 =  \dfrac{ - 4}{6} } \\  \\

\implies\sf{ \dfrac{ - 5 + 3}{3} =  \dfrac{ - 2}{3} } \\  \\

\implies\sf{ \dfrac{ - 2}{3}=  \dfrac{ - 2}{3} } \\  \\

LHS = RHS.

Hence, Verified.


Glorious31: Awesome
cαlypso: Nice
Anonymous: Fabulous!
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