Question

Plz answer this question ​

Answer 1

Answer:

10

Step-by-step explanation:

8+12+10+11+9= 50

=50/5

= 10

Answer 2

Answer

The median is a measure of middle most or a central tendency which gives the value of the middle most observation in a data.

Firstly we have to prepare cumulative frequency table

$\boxed{\begin{array}{|c|c|c|}\cline{1-3}\bf Class&\bf Frequency (f_i)&\bf cumulative \: frequency\\\cline{1-3}\sf 0-10&\sf 8&\sf 8 \\\cline{1-3}\sf 10-20&\sf 12&\sf 8+12=20\\\cline{1-3}\sf 20-30&\tt 10&\sf 8+12+10=30\\\cline{1-3}\sf 30-40&\sf 11&\sf 8+12+10+11=41\\\cline{1-3}\sf 40-50&\sf 9&\sf 8+12+10+11+9=50\\\cline{1-3}\sf &\sf \sum f_i= 50&\\\cline{1-3}\end{array}}$

we know that N = 50 and N/2 = 25

The cumulative frequency just greater than 25 is 30 and the corresponding class is 20-30

Median formula : $\boxed{ \sf M= l + \Bigg \{h \times \dfrac{ \bigg( \dfrac{N}{2} - cf \bigg)}{f} \Bigg \}}$

Here,

• l denotes lower limit of median class
• h denotes width of median class
• f denotes frequency of median class
• cf denotes cumulative frequency of the class preceding the median class
• N denotes sum of frequency

According to the question,

median class is 20-30

so, l = 20, h = 10, f = 10, cf = cf of preceding class = 20 and N/2 = 25

By substituting all the given values in the formula,

$\dashrightarrow\sf M= l + \Bigg \{h \times \dfrac{ \bigg( \dfrac{N}{2} - cf \bigg)}{f} \Bigg \}$

$\dashrightarrow\sf M= 20 + \Bigg \{10 \times \dfrac{ ( 25 - 20)}{10} \Bigg \}$

$\dashrightarrow\sf M= 20 + \bigg \{ 10 \times \dfrac{(5)}{10} \bigg \}$

$\dashrightarrow\sf M= 20 + (5)$

$\dashrightarrow\sf M= 25$

Thus, Median = 25

Know more :

$\dashrightarrow\sf Mean = \dfrac{ \sum f_i x_i}{ \sum f_i}$

$\dashrightarrow\sf Mode = x_{k} + \bigg \{h \times \dfrac{(f_{k} - f_{k - 1})}{(2f_{k} - _{k - 1} - f_{k + 1}} \bigg \}$