Question

(plz answer this question)36 kg gunpowder contains 27 kg nitre 5.4 kg charcoal and rest Sulphur find the percentage content of sulphur in the gunpowder

Answer 1

Total Mass = 36kg
Nitre = 27kg
Charcoal = 5.4 kg
The percent of gunpowder
={36 - (27 + 5.4)/36} × 100
=(36 - 32.4/36) × 100
=(3.6/36) × 100
=0.1 × 100
=10%

The percent of gun powder = 10%
I hope I solved your problem so please mark as brainly.

Answer 2

Gunpowder= { 36 - ( 27+ 5.4 / 36 )}*100

={36 - 32.4 /36} *100

= 3.6 / 36 *100

= 36/360*100

= 10%

Hope it helps you