plz answer this question?...
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Answered by
6
a=−2d=−2
tn=a+(n−1)d
t2=−2+(2−1)(−2)
=−2+(1)(−2)
=−2−2
t2=−4
t3=−2(3−1)(−2)
=−2+(2)(−2)
=−2−4
t3=−6
Answered by
3
let the first term be a and common difference be d,
a=-2 and d=-2
a2=a+d
=-2+(-2)
=-2-2=-4
a3=a+2d
=-2+2(-2)
= -2-4
=-6
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