Question

plz answer this question​

Answer 1

Step-by-step explanation:

q2) (x-y) ^2=x^2-2xy+y^2

sub x^2+y^2=20 xy=6

so (x-y) ^2=20-2*6=20-12=8

x-y=√8

q3) x^3-y^3=(x-y) (x^2+xy+y^2)

=9*(20+10) =270

Answer 2

Answer:

Ans 3 x³-y³=999

Sorry I don't know 2nd one