Question

plz answer this question
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Answer 1

Answer:

9999990

Step-by-step explanation:

Greatest 7 digit number = 9999999

Greatest 2 digit number = 99

Dividing ,

Quotient = 101010

Remainder = 9

Thus largest 7 digit number divisible by largest 2 digit number(99) = 9999999-9 = 9999990

Hence the answer is 9999990

Answer 2

Question:

Find the greatest 7-digit number that is exactly divisible by the greatest 2 digit number

Solution:

The greatest 7 digit number is 9999999

The greatest 2 digit number is 99

Divide 9999999 by 99  

$\sf\Large\qquad\quad\quad101010\\ \begin{array}{cc} \cline{2 - 2} \sf 99 )&\sf \ \ \ 9999999\\&\sf990 \downarrow\\ \cline{2-2}& \sf \ \ \ \ 999\\ &\sf \ \ - 990 \\\cline{2-2}& \sf \ \ \ \ \ \ \ \ \ \ \ 999\\ &\sf \ \ \ \ \ \ \ \ \ - 990 \\ \cline{2-2} & \sf \ \ \ \ \ \ \ \ \ \ \ \ 009 \end{array}\\\\\\ Divisor \rightarrow 99 \\ \\ Quotient \rightarrow 101010\\\\Remainder \rightarrow 9$

When we divide 9999999 by 99 we get remainder 9

Now subtract the remainder 9 from 9999999

$9999999-9\\\\=9999990$

Answer:

Therefore the greatest 7 digit number exactly divisible by 99 is 9999990

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