Question

plz answer this question

Answer 1

[0010001111]... Hello User... [1001010101]
Here's your answer...

Here are a few identities...

sin (90-A) = cos A
cos (90-A) = sin A
tan (90-A) = cot A

$\frac{ \sin(90 - a) \cos(90 - a) }{ \tan(90 - a) } \\ = \frac{ \cos(a) \sin(a) }{ \cot(a) } \\ = \frac{ \sin(a) \cos(a) }{ \frac{ \cos(a) }{ \sin(a) } } \\ = \frac{ \sin(a) \cos(a) \sin(a) }{ \cos(a) } \\ = { \sin }^{2} a$
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