Question

plz answer this question ​

Answer 1

Answer:

Step-by-step explanation:

ANSWER :-

☞ Dividing $(5x^{3}- x^{2} +6x-2)$ by $(2x-3)$

Step 1:-

➜Put Divisor =0

$(2x-3)=0\\or 2x=3\\or x=\frac{3}{2}$

Step 2:-

➜Let, P(x) = $(5x^{3} -x^{2} +6x-2)$

putting x = $\frac{3}{2}$

∴ P($\frac{3}{2}$) =

              $5(\frac{3}{2})^{3}-(\frac{3}{2})^{2}+6(\frac{3}{2})-2\\= 5(\frac{27}{8})-(\frac{9}{4})+9-2\\=\frac{135}{8}-\frac{9}{4}+9-2\\=\frac{135-18+72-16}{8} \\=\frac{173}{8}$

∴ Thus the remainder P(x) = $\frac{173}{8}$

Answer 2

Answer:

pls mark the above as BRAINLIEST