Physics, asked by nayakantiramadubbamm, 1 day ago

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Answered by gamahendra42
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Answer:

Two point charges are separated by a distance of 10.0cm. One has a charge of 25mu * C and the other + 50 * mu * C . (a) Determine the direction and magnitude of the electric field at a point P between the two charges that is 2.0 cm from the negative charge (b) If an electron (mass=9.11*10^ -31 kg) is placed at rest at P and then released, what will be its initial acceleration( direction and magnitude)? Q_{1} = - 25mu * C; *-r 1 =2.0 cm P Q_{2} = + 50 μC r_{2} = 8.0 cm

Answered by thisisadi273
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Answer:

sorry I don't know that but I think

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