Question

plz answer this question​

Answer 1

Let us consider,

Cost of one chair =Rs x and

Cost of one table =Rs y

As per the statement,

5x+4y=Rs 5600...(1)

4x+3y=Rs 4340....(2)

Using elimination method:

Multiply (1) by (3) and (2) by 4. And subtract both the equations.

15x+12y=16800

16x+12y=17360

− − −

_________________

−x =−560

So, x=560

From (1)

5×560+4y=5600

2800+4y=5600

4y=5600−2800

4y=2800

y=700

Answer

Cost of one chair =Rs 560

and cost of one table =Rs 700