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|=1A time=15 sec
We know that ,
1coloumb lsec
lamp = 1 c /s
1 = coloumb / 15
1co|oumb of charge of electron: 15C.
coloumb ampere
no. of electrons = coulmb / ampere
no. of electrons = 15 /1
Therefore, The no. of electrons flowing are 15
We know that ,
1coloumb lsec
lamp = 1 c /s
1 = coloumb / 15
1co|oumb of charge of electron: 15C.
coloumb ampere
no. of electrons = coulmb / ampere
no. of electrons = 15 /1
Therefore, The no. of electrons flowing are 15
Answered by
6
Hey Here is your Answer....
l = 1A
Time = 15 Sec
We know that,
1amp = 1coloumb/1sec
1 = coloumb/15
1coloumb of charge of electron = 15C.
no. of electrons = coloumb/ampere
no. of electrons = 15/1
Therefore, The number of electrons flowing are 15.
Hope it Helps you........
l = 1A
Time = 15 Sec
We know that,
1amp = 1coloumb/1sec
1 = coloumb/15
1coloumb of charge of electron = 15C.
no. of electrons = coloumb/ampere
no. of electrons = 15/1
Therefore, The number of electrons flowing are 15.
Hope it Helps you........
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