plz answer this question
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(i) the slope of position-time graph gives us velocity
slope= y component/x component
=> velocity= (30-10)/(3-2) = 20/1=20m/s
(ii) displacement is proportional to t^3
=> displacement=αt^3
where , "α" is constant of proportionality
=> velocity=d(displacement)/dt
=> velocity= d(αt^3)/dt
=> velocity= α3t^(3-1) =α3t^2
=> velocity is proportional to t^2
acceleration= d(velocity)/dt
=>acceleration= d(α3t^2)/dt
=> acceleration=6αt^(2-1) = 6αt
=> acceleration is proportional to t
=> acceleration is dependent on "t"
=> acceleration increases as time increases....
hope it helps you....
☺☺
slope= y component/x component
=> velocity= (30-10)/(3-2) = 20/1=20m/s
(ii) displacement is proportional to t^3
=> displacement=αt^3
where , "α" is constant of proportionality
=> velocity=d(displacement)/dt
=> velocity= d(αt^3)/dt
=> velocity= α3t^(3-1) =α3t^2
=> velocity is proportional to t^2
acceleration= d(velocity)/dt
=>acceleration= d(α3t^2)/dt
=> acceleration=6αt^(2-1) = 6αt
=> acceleration is proportional to t
=> acceleration is dependent on "t"
=> acceleration increases as time increases....
hope it helps you....
☺☺
viswamithr:
thankyou meenakshi
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