Question

Plz answer this question

Answer 1

Given AC=AB.

→ABC=ACB ( let it be x) [ Angles Opposite to equal Sides are Equal]

By Angle sum Prpty of triangle...
180°=36° +x+x (ABC=ACB)
→180-36=2(x)
→2(ACB)=144

→ACB=144/2=72°

(1),(2)→ACB=ABC=72°..

Now By Using Exterior angle Prpty...

ABC=ADB+DAB
→72°=45°+DAB
→DAB=72°-45°=27°...

(3)→DAB=27°

Same Prpty Using Again...

ACB=CEA+EAC
→72°=40°+EAC
→EAC=72°-40°=32°

(4)→EAC=32°

So
(1)ABC=72°
(2)ACB=72°
(3)DAB=27°
(4)EAC=32°

*I Marked Angles as (ABD ,EAC,...)

Hope it Helps...
Regards,
Leukonov.

Answer 2

Since AB=AC therefore angle ABC = angle ACB.
Again, angles ABC + ACB + BAC = 180°
ABC + ABC + BAC = 180 ° { since ABC = ACB}
2ABC + 36° = 180°
ABC = 72°

Therefore angle ABC = angle ACB = 72°

Now,
Angles DAB + ADB + ABD = 180°
DAB + 45° + (180°-72°) = 180°
DAB = 180° - 153°
DAB = 27°
Again,
Angles EAC + ACE + AEC = 180°
EAC + (180°-72°) + 40° = 180°
EAC = 180° - 148°
EAC = 32°

HOPE IT HELPS. THANK YOU