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no it's differentiable....at x =1
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kirtiprasanjenpchfhd:
in f(x) put the value of x
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The function lxl is not differentiable at x=0 and the function lx-2| is not differentiable at x-2=0 or x=2.
This implies that 2lxl +lx-2| is not differentiable at x=0,2
So the function is differentiable at everypoint except at x=0,2.
This implies that 2lxl +lx-2| is not differentiable at x=0,2
So the function is differentiable at everypoint except at x=0,2.
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