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let the required angle be x
let the other angle be (90 - x) as it is the complement of the other
(90-x) ------------------ (1)
90-x = (4/5)x
taking 5 to other side (cross multiply )
we get
450 - 5x = 4x
450 = 9x
x = 450/9
x = 50 ° -------------- (2)
subsituting 2 in 1 we get
(90-x )
(90 - 50)
=40 °
there fore the angles are 40 and 50
let the other angle be (90 - x) as it is the complement of the other
(90-x) ------------------ (1)
90-x = (4/5)x
taking 5 to other side (cross multiply )
we get
450 - 5x = 4x
450 = 9x
x = 450/9
x = 50 ° -------------- (2)
subsituting 2 in 1 we get
(90-x )
(90 - 50)
=40 °
there fore the angles are 40 and 50
kvnmurty:
good
Answered by
4
Answer- Complementary angles = 90°
Let 1 angle be x.
Its complement = 90°-x
Now, 90°-x=4/5x
Cross multiply 5 on both sides..
⇒ 450°- 5x= 4x.
⇒450°=9x
⇒x= 450°÷9
⇒x= 50°
So, complement of 50°= 90°-50°
= 40°
So, the angles are 40° and 50°..
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