Question

plz answer this question ​

Answer 1

Answer:

The mode of the given data is 65.625 hours.

Step-by-step explanation:

First we will find the modal class.

Here the modal class is 60 - 80 because it's frequency is the maximum of all.

Now the formula for mode is

L + ( f1 + f0 / 2f1 - f0 - f2 ) x h

So here

L is the lower class of modal class i.e. 60.

f1 is the frequency of modal class which is 61.

f0 is the frequency of the class preceding the modal class which is 52.

f2 is the frequency of the class succeeding (next to) the modal class which is 38

h is the class width  of modal class which is 80 - 60 = 20

So just substitute the values and you get

=60 + ( 61 - 52 / 2(61) - 52 - 38 ) x 20

= 60 + 45/8

= 60 + 5.625

= 65.625 hours

Hope you got the answer and mark me as brainliest if this helped you.