Math, asked by sanjay7631, 10 months ago

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Answered by gourimisale11
2

hi mate! your answer↓

area of triangle ABC=1/2×AB×AC

=1/2×3×4

=1/2×12

=6 sq.cm

in triangle ABC

by Pythagoras theorem

BC2= AB2+ AC2

=3^2+4^2

=9+16

=25

by taking square root

BC= 5 cm

radius of circle= BC/2=5/2=2.5cm

area of circle= πr^2

=3.14×2.5×2.5

= 19.62 sq.cm

area of shaded region= area of circle- area of triangle

= 19.62-6

=13.62 sq.cm

hope that this will help you


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Answered by harish1322
2

Hypo square = base square

BC^2=3^2 + 4^2

BC^2 =9+16

BC^2 =25

BC =UNDERROOT 25

BC =5cm

so radius of circle =5/2

=2.5 cm

area of circle = pie r square.

= 3.14 ×2.5 ×2.5

=19.625cm ^ 2

area of triangle = 1/2 base × height

= 1/2 ×4 ×3

= 6cm^2

area of shaded region = area of circle - area of triangle

=19.625 - 6

=13.625 cm square

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