plz answer this question asap
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Answer: t = 20.
Line L1: x - 2 y + 10 = 0 ---(1)
=> x = (2 y -10) -- (2)
Circle C: x² + y² = 100 ---(3)
Substitute (2) in (3) to get coordinates of B.
(2y-10)² + y² = 100
5y² - 40 y + 100 = 100
y = 0 or y = 8.
Substitute in (1) to get:
x = (2y-10) = -10 or 6
Point B is in 1st Quadrant. => B = (6 , 8)
Slope of Line L1 given: 1/2.
Slope of Line L2 ⊥ L1: -1/(1/2) = - 2
Line through B having a slope of -2 :
( y - 8)/(x-6) = -2
y + 2 x = 20 --- -(4)
This line cuts y - axis at (0, t). Substitute the coordinates in (4).
So: t + 2 * 0 = 20
t = 20.
Line L1: x - 2 y + 10 = 0 ---(1)
=> x = (2 y -10) -- (2)
Circle C: x² + y² = 100 ---(3)
Substitute (2) in (3) to get coordinates of B.
(2y-10)² + y² = 100
5y² - 40 y + 100 = 100
y = 0 or y = 8.
Substitute in (1) to get:
x = (2y-10) = -10 or 6
Point B is in 1st Quadrant. => B = (6 , 8)
Slope of Line L1 given: 1/2.
Slope of Line L2 ⊥ L1: -1/(1/2) = - 2
Line through B having a slope of -2 :
( y - 8)/(x-6) = -2
y + 2 x = 20 --- -(4)
This line cuts y - axis at (0, t). Substitute the coordinates in (4).
So: t + 2 * 0 = 20
t = 20.
kvnmurty:
:-)
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