Question

plz......answer this question Buddy​

Answer 1

Answer:

$\frac{ {9}^{n} \times {3}^{2} \times {3}^{n} - {27}^{n} }{ {3}^{3m} \times {2}^{3} } = > \frac{1}{27} = > \frac{ {3}^{2n} \times {3}^{2} \times {3}^{n} - {27}^{n} }{ {3}^{3m} \times {2}^{3} } \\ \\ \\ \\ = \frac{ {3}^{2n + 2 + n} - {3}^{3n} }{ {3}^{3m} \times {2}^{3} } = \frac{1}{27} \\ \\ \\ = > \frac{ {3}^{3n + 2} - {3}^{3n} }{ {3}^{3m} \times {2}^{3} } = \frac{1}{27} \\ \\ \\ = > \frac{ {3}^{3n} \times {3}^{2} - {3}^{3n} }{ {3}^{3m} \times {2}^{3} } = \frac{1}{27} \\ \\ \\ = > \frac{ {3}^{ 3n} (9 - 1)}{ {3}^{3m} \times 8} = \frac{1}{27} \\ \\ \\ = > \frac{ {3}^{3n} \times 8 }{ {3}^{3m} \times 8} = > \frac{ {3}^{3n} }{ {3}^{3m} } = > \\ \\ \\ = = = > > {3}^{3n} \times {3}^{ - 3m} = ( \frac{1}{3} ) ^{3} \\ \\ \\ = > {3}^{3n} \times {3}^{ - 3m} = {3}^{ - 3} \\ \\ = > 3n - 3m = - 3 \\ \\ \\ = > 3(n - m) = - 3 \\ \\ \\ \\ = > n - m = - 1 \\ = > - (m - n) = - 1 \\ \\ \\ = = = > > > (m - n) = 1 \: \: prove....$

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