Question

plz...answer this question fast​

Answer 1

Let

$27^{log2} = x$......(i)

Applying logarithm on both sides, we get

$log2log27=logx$

$log2*log3^3=logx$

$log2*3log3=logx$

$log2^3*log3=logx$

$log8*log3=logx$

$x=8^{log3}$......(ii)

Comparing equations (i) and (ii)

$27^{log2}=8^{log3}$

HENCE PROVED

Answer 2

may it's help you ......