plz answer this question fast .....
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Answered by
1
Hey!!!!
Let's Solve
=> (7x - 1) - (5x + 1/2) = x - (1 - x)/2
=> 7x - 1 - 5x - 1/2 = (2x - 1 + x)/2
=> 2x - 1 - 1/2 = (3x - 1)/2
=> (4x - 2 - 1)/2 = (3x - 1)2
Cancelling denominatora
=> 4x - 3 = 3x - 1
=> x = 2
Hope this helps
Let's Solve
=> (7x - 1) - (5x + 1/2) = x - (1 - x)/2
=> 7x - 1 - 5x - 1/2 = (2x - 1 + x)/2
=> 2x - 1 - 1/2 = (3x - 1)/2
=> (4x - 2 - 1)/2 = (3x - 1)2
Cancelling denominatora
=> 4x - 3 = 3x - 1
=> x = 2
Hope this helps
Answered by
1
(7x - 1) - (5× + 1/2) = 1 - (1 - x)/2
=>7x - 1 - 5x - 1/2 = 1 - (1 - x)/2
=>2x -3/2 = 1 - (1 - x)/2
=>2x + (1 - x)/2 = 1 + 3/2
=>(3x+1)/2 = 5/2
=>3x + 1 = 5
=>3x = 4
=>x = 4/3
HOPE THIS HELPS
MARK AS BRAINLIEST IF IT HELPS
REGARDS
=>7x - 1 - 5x - 1/2 = 1 - (1 - x)/2
=>2x -3/2 = 1 - (1 - x)/2
=>2x + (1 - x)/2 = 1 + 3/2
=>(3x+1)/2 = 5/2
=>3x + 1 = 5
=>3x = 4
=>x = 4/3
HOPE THIS HELPS
MARK AS BRAINLIEST IF IT HELPS
REGARDS
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