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abhishekpandeyp5a371:
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Hii..
i) no. of molecules = moles × Na ( Na is Avogadro's no.)
so, here it is one mole so molecules will be 1 × 6.023 × 10^-23
= 6.023 ×10^23
ii ) 1 mole of chlorine = 2 × 6.023 × 10^23 = 12.046×10^23 atoms
iii) mole = given weight ÷ molar weight
here, molecular weight = 2 × 35.5 = 71
so , 1 = weighs ÷ 71
weighs = 71 grams
___________
hope this helps !
i) no. of molecules = moles × Na ( Na is Avogadro's no.)
so, here it is one mole so molecules will be 1 × 6.023 × 10^-23
= 6.023 ×10^23
ii ) 1 mole of chlorine = 2 × 6.023 × 10^23 = 12.046×10^23 atoms
iii) mole = given weight ÷ molar weight
here, molecular weight = 2 × 35.5 = 71
so , 1 = weighs ÷ 71
weighs = 71 grams
___________
hope this helps !
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