Question

plz answer this question fast!!!!!!

Answer 1

Correct Answer is option 4) -- 125


$given \: p = 124 \\ \\ put \: the \: value \: of \: p \: in \: the \: given \: expression \\ \\ \sqrt[3]{124( {124}^{2} + 3 \times 124 + 3) + 1 } \\ \\ \sqrt[3]{124( {124}^{2} + 372 + 3) + 1 } \\ \\ \sqrt[3]{124( {124}^{2} + 375) + 1 } \\ \\ multipy \:124 \: with \: ( {124}^{2} + 375) \\ \\ \sqrt[3]{124 \times {124}^{2} + 124 \times 375 + 1} \\ \\ \sqrt[3]{ {124}^{3} + 46500 + 1}$

$\sqrt[3]{ {124}^{3} + 46501 } \\ \\ \sqrt[3]{1953125} \\ \\ \: calculate \: the \: root \\ \\ = > 125$