Question

plz answer this question fast and correctly​

Answer 1

Answer:

Given

initial velocity of helicopter (u) = 0

acceleration (a) = 42/n m/s^2

time (t) = 5s

final velocity of helicopter I. e when ball is released (v) =u + at = 210/n m/s

displacement (s) = ut + 1/2 at^2

= 21 x 25 / n

initial velocity of ball (u) = 210/n m/s

acceleration (a) = -10 m/s^2

time (t) = 17.5s

displacement (s) = ut +1/2 at^2

$\frac{21 \times 25}{n} = \frac{210}{n}( \frac{175}{10}) + \frac{1}{2}( - 10)( { \frac{175}{10}) }^{2} \\ \frac{21 \times 25}{n} = {175}( \frac{21}{n} - \frac{175}{20} ) \\ \frac{3}{n} = \frac{21}{n} - \frac{35}{4} \\ \frac{21}{n} - \frac{3}{n} = \frac{35}{4} \\ \frac{18}{n} = \frac{35}{4} \\ n = \frac{72}{35} \\ n = 2.057$