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Answer: ⇒ 2x/(x - 3) + 1/(2x + 3) + (3x + 9)/(x - 3) (2x + 3) = 0
By Multiplying throughout by (x - 3) (2x + 3), we get
⇒ 2x(2x + 3) + (x - 3) + 3x + 9 = 0
⇒ 4x² + 6x + x - 3 + 3x + 9 = 0
⇒ 4x² + 10x + 6 = 0
Divining eq by 2, we get
⇒ 2x² + 5x + 3 = 0
By using factorization method, we get
⇒ 2x² + 5x + 3 = 0
⇒ 2x² + 2x + 3x + 3 = 0
⇒ 2x(x + 1) + 3(x + 1) = 0
⇒ (x + 1) (2x + 3) = 0
⇒ x + 1 = 0 or 2x + 3 = 0
⇒ x = - 1, - 3/2
Here, x = - 1, - 3/2.
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