Question

plz answer this question fast in an a. p. if the 12th term is-13 and the sum of its 4 terms is 24,find the sum of its first 10 terms

Answer 1

Answer:

Let 1st term is ‘a’ & common difference is ‘d’

n^th term =a+( n-1)d

12th term =a +11d=(-13).......... eq^n.. 1

Now, sum of 1st four term,

(a)+(a+d)+(a+2d)+(a+3d)=24

» 4a+6d=24

» 2a+3d=12...... eq^n... 2

Now , eq^n.. 1×2

» 2a+22d=(-26)

Now you have two variable & two eq, so solve this & find the value of a & d then

Use the formula

Sum of n^th term = (n/2) { 2a+(n-1)d}

Put the value of n=10 & the value of ‘a’& ‘d’ that you get after solving both equation

Step-by-step explanation:

Answer 2

Answer:Given that :-12 th term of the A.P is −1

sum of firts four terms is 24

Let, the 1st term of the A.P is a.

and common difference of the A.P is d.

Answer is in attachment below...Hope this answer is helpful please mark as the brainliest answer have a great day ahead please thank my math answers.

sorry I am not able to answer the covalent bond question of yours as it is reported..