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Answer:
AC = 12 cm
Step-by-step explanation:
Given:- A Circle with centre O, AB is a chord and BOC is the diameter and OD ⊥ AB such that, OD = 6 cm
Now,
Let the radius of this circle be r
then, it diameter = 2r
Now,
In ΔBOD and ΔBCA
∠ABC = ∠DBO
∠ODB = ∠CAB = 90° [BOC is the diameter, thus angle formed in a semicircle will be 90°]
Thus,
ΔBOD ~ ΔBCA [By A.A Similarity]
Thus,
BO/BC = DO/AC [Corresponding parts of similar Triangles]
Now, we know that,
BO = r
BC = 2r
DO = 6 cm
Thus,
r/2r = 6/AC
1/2 = 6/AC
Cross multiplying we get,
AC × 1 = 6 × 2
AC = 12 cm
Thus,
AC = 12 cm
Hope it helped and believing you understood it........All the best
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