Math, asked by blue6y, 10 months ago

plz answer this question
full answer required
step by step​

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Answered by mirai123
0

Answer:

u^3-u^2+3u-2

u(u^2-u+3)-2

No, it is not.

Answered by raushan6198
1

Step-by-step explanation:

P(x) =x^3 - x^2 +3x - 2

For x-2 to be factor of p(x)

There must be [ p(2) =0 ]

Now put x=2 in p(x)

P(2) =2^3 - 2^2 +3×2 - 2

= 8- 4 +6 - 2

=14 - 6 =8

As p(0) =/ 0

Hence (x-2) is not factor of p(x)

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