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For finding the greatest no of children, we will take the HCF of the given quantities.
32 = 2*2*2*2*2
40 = 2*2*2*5
56 = 2*2*2*7
HCF = 2*2*2 => 8
So, max no of children whom these fruits can ne distrubuted equally are 8
Share of each fruit -:
- Orange => 32/8 => 4
- Banana => 40/8 => 5
- Mango => 56/8 => 7
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Hello sanjay,
Step-by-step explanation:
Please mark me as brainlest..
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