Question

plz answer this question in step by step explanation​

Answer 1

Step-by-step explanation:

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Answer 2

$\frac{3}{x - 1} + \frac{1}{x - 3} = \frac{4}{x - 2}$

$\frac{3(x - 3)1(x - 1)}{(x - 3)(x - 1)} = \frac{4}{x - 2} \\ \frac{3x - 9 + x - 1}{x ^{2} - x - 3x + 3 } = \frac{4}{x - 2} \\ \frac{4x - 10}{x^{2} - 4x + 3} = \frac{4}{x - 2} \\ (4x - 10)(x - 2) = 4(x ^{2} - 4x + 3) \\ 4x ^{2} - 8x - 10x + 20 = 4x^{2} - 16x + 12 \\ 4x ^{2} - 18x + 20 = 4x ^{2} - 16x + 12 \\ 4x^{2} - 4x^{2} - 18x + 16x + 20 - 12 = 0\\ - 2x + 8 = 0 \\ 8 = 2x \\ \frac{8}{2} = x \\ x = 4$

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