Question

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Answer 1

Answer:

2x+5+x+45+3x+2x-10=360

8x+40=360

8x=320

x=40

so now,

Internal angle=180-2x+5

=180-85

=95

180-x+45

=180-85

=95

Step-by-step explanation:

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Answer 2

Answer:

We know that the sum of all external angles of a quadrilateral is 360°.

Given Measures :

• 2x + 5, x + 45, 3x , 2x - 10 = 360°

Let's do :

$\sf \to \: 2x + 5 + x + 45 + 3x + 2x - 10 = 360 \\ \\ \to\sf \: 2x + x + 3x + 2x + 5 + 45 - 10 = 360 \\ \\ \sf\to \: 3x + 3x + 2x + 50 - 10 = 360 \\ \\ \sf\to \: 3x + 5x + 40 = 360 \\ \\ \sf\to \: 8x + 40 = 360 \\ \\ \sf\to8x = 360 - 40 \\ \\ \sf \to \: 8x = 320 \\ \\ \sf\to \: x = \frac{320}{8} \\ \\ \to\bf \: x = 40$

${\therefore {\frak{ x =40 }}}$

So , The angles are ;

$\sf\bullet \: \: 2x + 5 \\ \\ \to \sf \: 2 \times 40 + 5 \\ \\ \to \sf \: 80 + 5 \\ \\ \bf\to \: 85\degree$

$\bull\sf \: x + 45 \\ \\ \sf\to \: 40 + 45 \\ \\ \bf\to \: 85\degree$

$\bullet \: \sf 3x \\ \\ \to\sf \: \: 3 \times 40 \\ \\ \bf\to \: 120\degree$

$\bullet \sf \: 2x - 10 \\ \\ \sf\to \: 2 \times 40 - 10 \\ \\ \sf\to \: 80 - 10 \\ \\ \bf \to \: 70\degree$

= 85 + 85 + 120 + 70 = 360°

Hence, The external angles are 85° , 85° , 120° , 70°

Thus Solved !!