Question

Plz answer this question... It is 10th grade math question from polynomials...


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Answer 1

Step-by-step explanation:

Let one zero be y then another zero = 2y

Sum of zeros = -b/a

→y+2y= 3y= -b/a .

→y = -b/3a .....(1)

Product of zeros = c/a

→2y^2= c/a

→2(-b/3a)^2 = c/a. {from (1)}

→2b^2/9a^2= c/a

→2b^2= 9a^2c/a

→2b^2= 9ac .

Hence proved

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Let one zero be y then another zero = 2y

Sum of zeros = -b/a

→y+2y= 3y= -b/a .

→y = -b/3a .....(1)

Product of zeros = c/a

→2y^2= c/a

→2(-b/3a)^2 = c/a. {from (1)}

→2b^2/9a^2= c/a

→2b^2= 9a^2c/a

→2b^2= 9ac .

Hence proved