Question

Plz answer this question it is urgent

Find the sum of the first 13 terms of the AP 3/4,2/3,7/12,1/2,...

Answer 1

n=13

a=3/4

d=2/3 - 3/4

=-1/12

Sn = 13/2[2×3/4+(13-1)(-1/12)]

=13/2[3/2+(-1)]

=13/2[1/2]

=13/2×1/2

=13/4

so your answer is 13/4....

plzz mark it as brainliest......