Plz answer this question it is urgent
Find the sum of the first 13 terms of the AP 3/4,2/3,7/12,1/2,...
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n=13
a=3/4
d=2/3 - 3/4
=-1/12
Sn = 13/2[2×3/4+(13-1)(-1/12)]
=13/2[3/2+(-1)]
=13/2[1/2]
=13/2×1/2
=13/4
so your answer is 13/4....
plzz mark it as brainliest......
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