Math, asked by 5656mehta, 10 months ago

Plz answer this question it is very important

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Answered by Abhishek474241
3

\huge\star\underline{\mathcal\color{brown}{HELLO\:MATE}}\star

\color{brown}{HERE\:IS\:YR\:ANS}

✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶

\underline\color{Green}{ATTACHMENT}

SEE THE GIVEN ATTACHMENT

\fbox\color{brown}{HOPE\:IT\:HELPS}

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\huge{\mathcal{THANKS}}

.

 <marquee >☝️ABHI☝️

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Answered by vrushti444
1

1.

1. SOLUTION: p(x) = x2 -2√2x+1

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1 =1

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1 =1

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1 =1 HEY DEAR YOU ANSWER IS #1...

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1 =1 HEY DEAR YOU ANSWER IS #1... PLEASE MARK AS BRAINLIST.....

1. SOLUTION: p(x) = x2 -2√2x+1 p(2) = (2)2-2(2) +1 =4-4+1 =1 HEY DEAR YOU ANSWER IS #1... PLEASE MARK AS BRAINLIST..... THANKYOU☺

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